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"Love you op " | |||
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"Did his neighbours see him through the kitchen window " Hmmm....this is a possible variable I didn’t factor into the proceedings; Indeed, if he performed his measurements in haste after being spotted, he may have invalidated his recorded findings..... | |||
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"42? " That sounds about right to me; I have no idea the answers myself as I only got an ‘E’ (for excellence obviously) in maths at GCSE level | |||
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"Weight of bollocks 1.3 stone. A single bollock half of that. As a percentage (12.4/13.7)*100=90, so the bollocks are approx 10% With one bollock he weighs 13.7-0.65 = 13.35 " Great workings out With his balls making up an approximate tenth of his total body weight, I think that the next digits Dave should seriously be considering, should be his Doctor’s phone number.....rather urgently... | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck " When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. " For accuracy, shouldn't that be b+b-c or 2b-c ? | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. For accuracy, shouldn't that be b+b-c or 2b-c ? " No it must be 2b+c=1.3 stone. But who decimalised stones any way, 1.3 stone should actually be 1 stone 4 1/5 ounces. | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. For accuracy, shouldn't that be b+b-c or 2b-c ? No it must be 2b+c=1.3 stone. But who decimalised stones any way, 1.3 stone should actually be 1 stone 4 1/5 ounces. " I think it has been established that 2b+c =1.3 stones. So therefore to find the correct weight for 2 bollocks must be 2b-c ? Unless of course the cock was so small that it made no difference to the reading on the scales | |||
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" I think it has been established that 2b+c =1.3 stones. So therefore to find the correct weight for 2 bollocks must be 2b-c ? Unless of course the cock was so small that it made no difference to the reading on the scales " But it would still need to be 2b=1.3-c Tell Dave to go back and weigh his cock. Cal | |||
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"If he dipped his balls into a tank of water and took note of how much he displaces, then take the density of balls (I'm sure there's a chart for that somewhere) he could work out how much they weighed" Eureka! Archimedes would indeed concur on this course of scientific action We know that Dave’s balls are fairly sizeable so he’ll need to lower them into a bath tub of water (being simultaneously mindful not to lower any other part of himself in of course and equally as important, noting the exact volume of water introduced). The good news is, the said technique will also give an accurate gauge as to his penile mass in addition from the water volume displacement | |||
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"If he dipped his balls into a tank of water and took note of how much he displaces, then take the density of balls (I'm sure there's a chart for that somewhere) he could work out how much they weighed Eureka! Archimedes would indeed concur on this course of scientific action We know that Dave’s balls are fairly sizeable so he’ll need to lower them into a bath tub of water (being simultaneously mindful not to lower any other part of himself in of course and equally as important, noting the exact volume of water introduced). The good news is, the said technique will also give an accurate gauge as to his penile mass in addition from the water volume displacement " And he'd have squeaky clean balls | |||
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"Weight of bollocks 1.3 stone. A single bollock half of that. As a percentage (12.4/13.7)*100=90, so the bollocks are approx 10% With one bollock he weighs 13.7-0.65 = 13.35 " The maths is right but the physics is wrong. As soon as he touches anything, however lightly, the weight read by the scales is going to inaccurate. The only way you could this experiment properly be done would be to cut his balls of completely. Then, assuming no significant blood loss, he could weigh himself again and subtract it from the first to get the weight of his balls. Alternative, having cut his balls of, he could just weigh them directly (thus avoiding any errors caused by excessive blood loss). | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. For accuracy, shouldn't that be b+b-c or 2b-c ? No it must be 2b+c=1.3 stone. But who decimalised stones any way, 1.3 stone should actually be 1 stone 4 1/5 ounces. " So b = (1.3 - c)/2 If it wasn't for the flaw in the Physics he could find the value of c by putting 2b below the sink lip. | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck When Dave balanced his balls on the edge of the sink the weight of his penis was also lost regardless of how big his balls were. The 1.3 stone therefore = b + b + c or 2b + c. For accuracy, shouldn't that be b+b-c or 2b-c ? No it must be 2b+c=1.3 stone. But who decimalised stones any way, 1.3 stone should actually be 1 stone 4 1/5 ounces. I think it has been established that 2b+c =1.3 stones. So therefore to find the correct weight for 2 bollocks must be 2b-c ? Unless of course the cock was so small that it made no difference to the reading on the scales " No, the correct weight of 2b would be 1.3-c. | |||
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"I wonder how many men are trying to weigh their balls now." I'm weighting for someone to weigh them for me. | |||
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"18lb. 9lb per ball?? " Very sexy pics for someone who says they're a geek. xx | |||
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"Weight of bollocks 1.3 stone. A single bollock half of that. As a percentage (12.4/13.7)*100=90, so the bollocks are approx 10% With one bollock he weighs 13.7-0.65 = 13.35 " If his balls were in the sink where is his dick ? The weight of that has not been mentioned. Don’t go to his house as just think you may end up washing your hands at some point | |||
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"Weight of bollocks 1.3 stone. A single bollock half of that. As a percentage (12.4/13.7)*100=90, so the bollocks are approx 10% With one bollock he weighs 13.7-0.65 = 13.35 If his balls were in the sink where is his dick ? The weight of that has not been mentioned. Don’t go to his house as just think you may end up washing your hands at some point " His dick is hanging unsupported, so it's part of the body weight. Unless he's laid it out over his bollocks, which would be supported. But if he got a stiffy, it would again become part if the bodyweight. So bearing that in mind, his cock had been excluded for such reasons. If the sink is chilly, he'll suffer shriveled scrotum. Again a significant factor in bloodflow and subsequent weight changes. | |||
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"In the interests of keeping your brains fit and functional..... One evening Dave (whilst heavily inebriated) decides for reasons best known only unto himself, to measure exactly how much his bollocks weigh. Being mindful of the correct scientific technique, he firstly stands himself on some bathroom scales and determines that he presently weighs in at 13.7 stones. Next, rearranging the scales by his sink unit, Dave weighs himself again, this time carefully balancing his balls on the edge of the sink. He notices that according to the scales, he now weighs 12.4 stones exactly (oh, I forgot to mention that Dave has extraordinarily large balls, possibly as a result of either a) Elephantiasis or b) Exposure to Gamma radiation or something.....but I digress) Anyhoo, here is the question for you: A) How much do Dave’s balls actually weigh.....as a percentage of his total body weight? B) Assuming that each testicle is the same weight, if by some freak accident, one of Dave’s balls were to fall off, how much would he subsequently weigh? Good luck " 10% and 11.1 stone but this is ballox | |||
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"Maybe he could weigh himself again while I gently lift his balls " 2stone 6pound ballox you'll have to use two hands | |||
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"Dave's a knob.. " And also a Repeater Good old Dave | |||
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"Yeah but if train A leaves the station at a speed of 70kph and heads towards Daves bollocks 20miles away is he in a fit state and strong enough to pick them up off the track in time" You have a real thing for removing body parts!! | |||
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"Yeah but if train A leaves the station at a speed of 70kph and heads towards Daves bollocks 20miles away is he in a fit state and strong enough to pick them up off the track in time You have a real thing for removing body parts!! " Haha have hobnob | |||
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"Yeah but if train A leaves the station at a speed of 70kph and heads towards Daves bollocks 20miles away is he in a fit state and strong enough to pick them up off the track in time You have a real thing for removing body parts!! Haha have hobnob " I get scared when you’re nice to me | |||
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