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"7 + 7 / 7 + 7 x 7 - 7=?" Using bodmas, 7/7=1. 7*7=49 7+1+49-7= 50. Its easier when I write it out! | |||
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"The absence of brackets makes it 50, though I can see why some people imply the brackets when it's written in print. Interestingly they don't call it BODMAS nowadays, but BIDMAS. The 'I' standing for 'indicies'. In my day the 'o' stood for 'of', then it became 'order', bloody progress... Mr ddc" Was helping my ten year old last night when I noticed this. How many people do you reckon can remember "the formulae" for simultaneous equations? We always got told you don't have to remember it, as it will be given to you. BANG!!! In it went. Never to be forgotten. | |||
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"The absence of brackets makes it 50, though I can see why some people imply the brackets when it's written in print. Interestingly they don't call it BODMAS nowadays, but BIDMAS. The 'I' standing for 'indicies'. In my day the 'o' stood for 'of', then it became 'order', bloody progress... Mr ddc" Now o is for operations I think. | |||
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"From what I can see to my mind I have the same answer as ONE other person on this thread..." Show us how you did it then. And I'll show you why its wrong. | |||
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"Haven't got enough fingers so I'll go with 10 " I could teach you the ancient Babylonian finger-counting method where you can get up to 144. I'd like to pretend I needed it for the 'How many people have you slept with?' thread, but I'd be lying | |||
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"7+7=14 7+(7×7)-7= 7-7+49=49 14÷49=0.2857142857 Professor Mathmite " Sorry prof. I know your way cleverer than me on most thing but on this you're wrong. If no brackets you should use B - Brackets (), {} or [] O - Of (similar to multiply) D - Division / M - Multiplication * A - Addison + S - Subtraction - Which gives 50, as had been shown. Sorry, had to be done QEF | |||
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"BID or BOD, makes no difference there are only two types of mathematical operation. MULTIPLICATION: This includes division (which is just an inverted multiplication) and indexes or of (which is just many multiplications) ADDITION: This includes subtraction (which is just a negative addition) The actual or for doing any equation is Multiplication them Addition. The order of operations with in the two groups actually does not matter. Finally, if we really want, we can actually reduce the number of mathematical operations to one as Multiplication is just many additions. So, the long and short of it is, all that time they spent teaching you arithmetic at school they wasted because they never told you the simple truth. The only thing you can ever do with numbers is add them and nothing else. " Isn't addition just a negative subtraction? | |||
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"0 (Zero)" Can you show your workings out please? | |||
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"0 (Zero) Can you show your workings out please? " I'm guessing ((7+7)/(7+7)x7)-7 = 0 | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0" Working left to right not using BODMAS. | |||
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"It's still 7+(7/7)+(7*7)-7=50 though!" BODMAS wins of course. | |||
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"You have to use bodmas. Its the recognised method used in mathematics." It is. I have been wondering why and who first used it. | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0 Working left to right not using BODMAS. " That's not quite working left to right though. Working left to right would be (((((7+7)/7)+7)×7)-7) = ((((14/7)+7)×7)-7) = (((2+7)×7)-7) = (9×7)-7 = 63-7 = 56 The answer giving zero requires addition first, then division, then multiplication, (or multiplication then division), then subtraction, which is just weird. | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0" No it's 7 + 7 / 7 + 7 x 7 - 7 goes to 7+(7/7)+(7*7)-7 goes to 7+1+49-7 goes to 7-7+49+1 goes to 50 | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" Ooo look a squirrel | |||
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"It's still 7+(7/7)+(7*7)-7=50 though!" I guess I should have read the full thread first. | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0 No it's 7 + 7 / 7 + 7 x 7 - 7 goes to 7+(7/7)+(7*7)-7 goes to 7+1+49-7 goes to 7-7+49+1 goes to 50" You've not read a lot of the thread, have you? I was answering the question on the working used to get 0 as the answer. I quoted the question and then said my guess at the working used was that. My answer, 50, is much higher up the thread. But thanks for thinking I'm innumerate. | |||
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"It's still 7+(7/7)+(7*7)-7=50 though! I guess I should have read the full thread first. " Or at least read the post I quoted on that answer. It's ok though. I'm not offended. Much. | |||
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"You have to use bodmas. Its the recognised method used in mathematics. It is. I have been wondering why and who first used it. " Well I was taught it in the early eighties. My primary school maths teacher was just coming up to retirement. So its at least 40 years old! Its just a standard notation for maths. Like we have for IUPAC for physics and chemistry. | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0 No it's 7 + 7 / 7 + 7 x 7 - 7 goes to 7+(7/7)+(7*7)-7 goes to 7+1+49-7 goes to 7-7+49+1 goes to 50 You've not read a lot of the thread, have you? I was answering the question on the working used to get 0 as the answer. I quoted the question and then said my guess at the working used was that. My answer, 50, is much higher up the thread. But thanks for thinking I'm innumerate." Sorry, and I already said so while you were writing this. I didn't know how numerate you might be but, if I didn't think you were quite intelligent, I wouldn't have pointed out that I thought you were wrong and why. I now know that you are not only intelligent (something I've been able to tell from your other posts on other threads) but also numerate to. And, in case it sounds like I'm being sarcastic, I'm not. I mean it. | |||
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"It's still 7+(7/7)+(7*7)-7=50 though! I guess I should have read the full thread first. Or at least read the post I quoted on that answer. It's ok though. I'm not offended. Much." We really must stop crossing like this. | |||
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"0 (Zero) Can you show your workings out please? I'm guessing ((7+7)/(7+7)x7)-7 = 0 No it's 7 + 7 / 7 + 7 x 7 - 7 goes to 7+(7/7)+(7*7)-7 goes to 7+1+49-7 goes to 7-7+49+1 goes to 50 You've not read a lot of the thread, have you? I was answering the question on the working used to get 0 as the answer. I quoted the question and then said my guess at the working used was that. My answer, 50, is much higher up the thread. But thanks for thinking I'm innumerate. Sorry, and I already said so while you were writing this. I didn't know how numerate you might be but, if I didn't think you were quite intelligent, I wouldn't have pointed out that I thought you were wrong and why. I now know that you are not only intelligent (something I've been able to tell from your other posts on other threads) but also numerate to. And, in case it sounds like I'm being sarcastic, I'm not. I mean it." Hands up if you can't understand that......just me then! | |||
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"You have to use bodmas. Its the recognised method used in mathematics. It is. I have been wondering why and who first used it. Well I was taught it in the early eighties. My primary school maths teacher was just coming up to retirement. So its at least 40 years old! Its just a standard notation for maths. Like we have for IUPAC for physics and chemistry." I had a quick Google,it seems no one person has put their claim to it. I used to love maths,now it just gives me a headache. | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" Party 7! | |||
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"16 using bodmas method." 50 using BODMAS! | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" Partyyyyyyyy time | |||
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"I make it zero" how? | |||
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"7 + 7 / 7 + 7 x 7 - 7=? BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 " Thats BODMSA 7/7 = 1 7x7 = 49 7+1+49-7 = 50 | |||
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"I make it zero how?" (((7+7)/(7+7))*7)-7 and (7+7)/(7+7)*(7-7) both work out to 0 (And NO this is not my answer in case anyone is confused) | |||
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"7 + 7 / 7 + 7 x 7 - 7=? BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 Oh sod Thats BODMSA 7/7 = 1 7x7 = 49 7+1+49-7 = 50 " | |||
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"since there are some mathematical geniuses on here, could someone help me with the following probability of throwing exactly 2 sixes in 3 throws probability of throwing at least 2 sixes in 3 throws " . The main probability is two big gorillas taking you from the casino and giving you a probability lesson | |||
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"Strewth VV, you're a six addict" Only after I deleted the first of my posts in which I'd put 2's instead of 6's. | |||
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"She's not stated what she's throwing!" Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though. | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though." . Lol no I meant one dice or two! | |||
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"since there are some mathematical geniuses on here, could someone help me with the following probability of throwing exactly 2 sixes in 3 throws probability of throwing at least 2 sixes in 3 throws " Lmfao! This is a joke. I got it. | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two!" I'm better at English than I am Maths, so that would be one die and two dice (plural). | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). " . That was a spelling mistake.. I meant is she throwing one mice or two | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two " Sorry, can't help with your mice, I have my old stats text book out to work out what was niggling me. Borrow a cat from someone? | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two " In that case, isn't it heads or tails? | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two In that case, isn't it heads or tails? " Probably. I doubt there will be much left after the cat has had them | |||
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"98" How?? | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" the question hasnt used brackets therefore bodmas isnt the term used otherwise it would look like this within algebra 7 + ( 7 / 7 + 7 - 7 )= | |||
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"00111000 (bi) 38 (hex)" Nope. Binary (8-bit) 00110010 Hex 32 | |||
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"00111000 (bi) 38 (hex) Nope. Binary (8-bit) 00110010 Hex 32" I was looking at tertiary earlier but couldn't be bothered | |||
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"00111000 (bi) 38 (hex) Nope. Binary (8-bit) 00110010 Hex 32 I was looking at tertiary earlier but couldn't be bothered " That's the last thing I'd look at. | |||
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"00111000 (bi) 38 (hex) Nope. Binary (8-bit) 00110010 Hex 32 I was looking at tertiary earlier but couldn't be bothered That's the last thing I'd look at. " I like threes | |||
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"00111000 (bi) 38 (hex) Nope. Binary (8-bit) 00110010 Hex 32 I was looking at tertiary earlier but couldn't be bothered That's the last thing I'd look at. I like threesomes " Corrected your typo | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" 56 | |||
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"7 + 7 / 7 + 7 x 7 - 7=?56" Without BODMAS it would be 7+7=14, 14 divided by 7 = 2, 2 + 7 = 9, 9 x 7 = 63, 63 - 7 = 56. | |||
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"98 How??" I'm assuming that 7/7 means 7 over 7 otherwise known as 7 divided by 7 which equals 1. The sum therefore is 7+1=8 8+7=15 15x7=105 105-7=98 | |||
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"50 (regardless of brackets the same order applies) " Completely wrong (7+7)/7+7*7-7 =54 (7+7)/(7+7)*7-7 = 0 Try any of these combinations in a scientific calculator or a spreadsheet if you don't believe me. Spreadsheets and calculators were designed by mathematicians | |||
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"50 (regardless of brackets the same order applies) Completely wrong (7+7)/7+7*7-7 =54 (7+7)/(7+7)*7-7 = 0 Try any of these combinations in a scientific calculator or a spreadsheet if you don't believe me. Spreadsheets and calculators were designed by mathematicians " I meant the order of operations so brackets or not it still scans division-multiplication-addition-subtraction so 7+1+49-7=50 | |||
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"Definitely 50, the division and the multiplication take priority, then the addition and subtraction, working left to right." | |||
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"But there are no brackets in the given example, so again the order of operations is and always will be division-multiplication-addition-subtraction " I don't think any one numerate is disagreeing with you. Your previous post appeared to be saying brackets didn't matter - you've now clarified what you meant | |||
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"But there are no brackets in the given example, so again the order of operations is and always will be division-multiplication-addition-subtraction " Ah, the "regardless of brackets" mislead me. I thought you meant that even if there were brackets, and regardless of where they were, the answer would still be 50. | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" That's numberwang | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" 7/7=1 7 x 7= 49 7 + 1 + 49 = 57 57 - 7 = 50 BODMAS | |||
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"7 + 7 / 7 + 7 x 7 - 7=? " KISS 7/7=1 7 x 7= 49 1+49=50 It's arithmetic, not maths. As has been said above, it simply resolves down to addition. There are only ten digits, 0 to 9 , how hard can it get? The sad part is, as with the matter of parentheses (brackets) or "two sixes" question, many many schools/teachers are dreadful at setting questions carefully and accurately. | |||
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"I ran out of fingers after 10 ???" | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two " Mathematics SKE module D4 Throwing one mice 3 times 3 sixes= 1/6 x 1/6 x 1/6 = 1/216 2 sixes= 1/6 x 1/6 x 5/6 = 5/216 the next question was the probability of at least 2 sixes, I put 1/6 x 1/6 x 6/6 = 6/216 ie 1/36 but it got marked wrong not sure what to try now! | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two Mathematics SKE module D4 Throwing one mice 3 times 3 sixes= 1/6 x 1/6 x 1/6 = 1/216 2 sixes= 1/6 x 1/6 x 5/6 = 5/216 the next question was the probability of at least 2 sixes, I put 1/6 x 1/6 x 6/6 = 6/216 ie 1/36 but it got marked wrong not sure what to try now! " Cribbage? Snap? | |||
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"7 + 7 / 7 + 7 x 7 - 7=? BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 Thats BODMSA 7/7 = 1 7x7 = 49 7+1+49-7 = 50 " You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) | |||
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"7 + 7 / 7 + 7 x 7 - 7=? BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 Thats BODMSA 7/7 = 1 7x7 = 49 7+1+49-7 = 50 You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS)" I would suspect that a fair number see that there are no brackets and simply give up or guess. At least with multiple choice questions people are gonna gain a few marks even for wild guessing. | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS)" No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication " | |||
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"7 + 7 / 7 + 7 x 7 - 7=?" The number of time we shared a 7 up?....that would be 0 | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication " Nice but when written correctly as 12 ------ 3 * 2 Or 12 ----- * 2 3 then you can see clearly that multiplying 12 by 2 and divide by 3 is the same as 12 divided by 3 and then multiplied by 2, unlike the first one which is a completely different equation. So, always working from right to left:- 12/3*2 = 12*2/3 = 2/3*12 As long as 3 is the divisor the order does not matter. For any other answer you require brackets. | |||
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"Can we try it with eights instead " Make it interesting, with eighths. | |||
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"Can we try it with eights instead Make it interesting, with eighths. " Sorry, the only fractions I do are ¼ ½ ¾ | |||
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"I have never ever heard of BODMAS, and I took my maths o-level early." They had a different syllabus if the exam was in the afternoon? | |||
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"I have never ever heard of BODMAS, and I took my maths o-level early. They had a different syllabus if the exam was in the afternoon?" | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication " Setting aside the comments made further up, since they've been well covered, 12/(3*2)=3 Really? | |||
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"7 + 7 / 7 + 7 x 7 - 7=? BODMAS 7/7=1 then 7x7=49 then 7-7=0 so 1+49= 50 Thats BODMSA 7/7 = 1 7x7 = 49 7+1+49-7 = 50 You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) I would suspect that a fair number see that there are no brackets and simply give up or guess. At least with multiple choice questions people are gonna gain a few marks even for wild guessing. " It's C. AmIright? | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two Mathematics SKE module D4 Throwing one mice 3 times 3 sixes= 1/6 x 1/6 x 1/6 = 1/216 2 sixes= 1/6 x 1/6 x 5/6 = 5/216 the next question was the probability of at least 2 sixes, I put 1/6 x 1/6 x 6/6 = 6/216 ie 1/36 but it got marked wrong not sure what to try now! " Use a matrix.. 1 1|1 2|1 3|1 4|1 5|1 6 ----------------------- 2 1|1 2|2 3|2 4|2 5|2 6 ----------------------- 3 1|3 2|3 3|3 4|3 5|3 6 ----------------------- 4 1|4 2|4 3|4 4|4 5|4 6 ----------------------- 5 1|5 2|5 3|5 4|5 5|5 6 ----------------------- 6 1|6 2|6 3|6 4|6 5|5 6 The rows represent one die and the columns the other. | |||
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"She's not stated what she's throwing! Indeed she hasn't. I couldn't see if I could work it out if I assumed it was a javelin or a sickie though.. Lol no I meant one dice or two! I'm better at English than I am Maths, so that would be one die and two dice (plural). . That was a spelling mistake.. I meant is she throwing one mice or two Mathematics SKE module D4 Throwing one mice 3 times 3 sixes= 1/6 x 1/6 x 1/6 = 1/216 2 sixes= 1/6 x 1/6 x 5/6 = 5/216 the next question was the probability of at least 2 sixes, I put 1/6 x 1/6 x 6/6 = 6/216 ie 1/36 but it got marked wrong not sure what to try now! Use a matrix.. 1 1|1 2|1 3|1 4|1 5|1 6 ----------------------- 2 1|1 2|2 3|2 4|2 5|2 6 ----------------------- 3 1|3 2|3 3|3 4|3 5|3 6 ----------------------- 4 1|4 2|4 3|4 4|4 5|4 6 ----------------------- 5 1|5 2|5 3|5 4|5 5|5 6 ----------------------- 6 1|6 2|6 3|6 4|6 5|5 6 The rows represent one die and the columns the other. " What other? The question is about throwing one die three times. | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication Setting aside the comments made further up, since they've been well covered, 12/(3*2)=3 Really? " Ha ha ha! I never even noticed that. | |||
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" You can actually put the ODM or the AS parts in any order but you must put the B first then the ODM and finally the AS. Maybe it should be writing B(ODM)(AS) No you can't 12/3*2 = 8 12/(3*2) = 3 Division always precedes multiplication Setting aside the comments made further up, since they've been well covered, 12/(3*2)=3 Really? Ha ha ha! I never even noticed that. " I checked 3 times that I wasn't going mad before I posted it. I was a bit | |||
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