FabSwingers.com mobile

Join us FREE, we're FREE to use

Web's largest swingers site since 2006.

Already registered?
Login here

Back to forum list
Back to The Lounge

Maths question for Greedy Thump and others.

Jump to newest
 

By (user no longer on site) OP   
over a year ago

How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile?

Reply privatelyReply in forumReply +quote
 

By *ing and RideCouple
over a year ago

stockport

What the fuck????

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

2

Reply privatelyReply in forumReply +quote
 

By *londeCazWoman
over a year ago

Arse End of the Universe, Cumbria

I seem to remember reading somewhere that it'd be about 30 folk...can't remember the reasoning behind that though

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

It's getting late in the evening for all this lol

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"

How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile?"

Oh come on..I can't be expected to know that?...

Reply privatelyReply in forumReply +quote
 

By *icketysplitsWoman
over a year ago

Way over Yonder, that's where I'm bound

You only need a relatively small number of people to get a likelihood of sharing the birthday (not the birth date). I heard a programme on R4 years ago but I can't remember the number.

I do know that when I ran an organisation with 28 staff two of them shared my birthday.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

Why Greedy ????

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"What the fuck????"

Put it this way, if you and i walked into a pub with 35 people in it, and i bet you £10 that at least two people would share the same birthday, would you accept the bet?

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

The answer is always 42

Reply privatelyReply in forumReply +quote
 

By *icketysplitsWoman
over a year ago

Way over Yonder, that's where I'm bound


"I seem to remember reading somewhere that it'd be about 30 folk...can't remember the reasoning behind that though"

It is a number like that and I sort of understood it when it was explained on the R4 but it's all too clever for me to hold in my funny brain.

Reply privatelyReply in forumReply +quote
 

By *ing and RideCouple
over a year ago

stockport

I feel I am beginning to loose the will to live.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"Why Greedy ????"

Cos on another thread he mentions a (maths) question about 66 handshakes.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

2 out of 17 at work last year shared same birthday and one of them was me.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"Why Greedy ????

Cos on another thread he mentions a (maths) question about 66 handshakes.

"

Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben )

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"Why Greedy ????

Cos on another thread he mentions a (maths) question about 66 handshakes.

Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben ) "

you can fuxx off now

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me. "

bet you a £10 they do next year as well?

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

When I worked for a high street bank, part of the way data arrived in HR files was to sort all staff by birthday. It was striking in a sample of the population like that just how many people shared the same date.

Btw, to me, we were staff. Not frickin colleagues or any other such management bull that was used at the time.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"Why Greedy ????

Cos on another thread he mentions a (maths) question about 66 handshakes.

Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben )

you can fuxx off now "

Nah you lurve me really

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago

In reality, the spread of birth dates is not random, think of the onset of darker nights and power cuts to name but two.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"Why Greedy ????

Cos on another thread he mentions a (maths) question about 66 handshakes.

Thank god as for one min I thought you thought he was Einstein!!! (Sorry Ben )

you can fuxx off now

Nah you lurve me really "

Reply privatelyReply in forumReply +quote
 

By *ScotsmanMan
over a year ago

ayrshire

2

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?"

Nope cos the guy left

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?

Nope cos the guy left "

What, he's changed his birthday because he's left? I feel a Victor Meldrew moment coming on.

Reply privatelyReply in forumReply +quote
 

By *icketysplitsWoman
over a year ago

Way over Yonder, that's where I'm bound


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?

Nope cos the guy left "

He will still share your birthday unless one of you dies.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

It's 367

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?

Nope cos the guy left

He will still share your birthday unless one of you dies.

"

Yes but he won't be part of the how many are needed thingy , that was the original question.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?

Nope cos the guy left

He will still share your birthday unless one of you dies.

Yes but he won't be part of the how many are needed thingy , that was the original question. "

Are we not allowed to ask newer questions part way down?

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"2 out of 17 at work last year shared same birthday and one of them was me.

bet you a £10 they do next year as well?

Nope cos the guy left

He will still share your birthday unless one of you dies.

Yes but he won't be part of the how many are needed thingy , that was the original question.

Are we not allowed to ask newer questions part way down?"

You can ask whatever you want I don't mind

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

There must be an equation for it. So many days in month x months of year divided by people who wear rubber knickers kind of thing

Reply privatelyReply in forumReply +quote
 

By *icketysplitsWoman
over a year ago

Way over Yonder, that's where I'm bound


"There must be an equation for it. So many days in month x months of year divided by people who wear rubber knickers kind of thing "

There is, there is... if only I could remember what the clever person on R4 said I would tell you.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

It's 367 ..

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"

How many people would need to be in any random grouping, so that an each way bet (ie my £10 v your £10) that at least two people share the same date of birth ( not year though) would be worthwhile?"

Possibility... 2

Probability....366

Median.... Somewhere in between...

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago

Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?

Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half.

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"It's 367 .. "

In a leap year...

Reply privatelyReply in forumReply +quote
 

By (user no longer on site)
over a year ago


"It's 367 ..

In a leap year..."

Correct !!

Reply privatelyReply in forumReply +quote
 

By (user no longer on site) OP   
over a year ago


"Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?

Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half."

Coconut to the lady. Well done.

Reply privatelyReply in forumReply +quote
 
 

By (user no longer on site)
over a year ago


"Example 3.3 How many people do we need to have in a room to make it a favorable bet (probability of success greater than 1/2) that two people in the room will have the same birthday?

Since there are 365 possible birthdays, it is tempting to guess that we would need about 1/2 this number, or 183. You would surely win this bet. In fact, the number required for a favorable bet is only 23. To show this, we find the probability pr that, in a room with r people, there is no duplication of birthdays; we will have a favorable bet if this probability is less than one half.

Coconut to the lady. Well done.

"

I asked google

Reply privatelyReply in forumReply +quote
Post new Message to Thread
back to top