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For mathematicians only

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By *idingout41 OP   Man
over a year ago

Southampton

I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

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By (user no longer on site)
over a year ago


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?"

I've read this 3 times and I think the answer is Faraday Cage

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By *ensualtouch15Man
over a year ago

ashby de la zouch


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?"

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions

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By (user no longer on site)
over a year ago

Bit of a bright spark eh

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By *vbride1963TV/TS
over a year ago

E.K . Glasgow


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?"

Only if you’ve left them on for ever then get a big leckie bill .

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By *ce WingerMan
over a year ago

P.O. Box DE1 0NQ

Sorry, I only do arithmetics innit

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By *oss and SuzieCouple
over a year ago

Porthmadog

You can think of the configuration of 8 switches as an 8 digit binary word where 00000000 represents all switches off and 11111111 represents all switches on. All states can be represented. For instance, 01000000 would be just the second switch on.

The number of combinations is given by the maximum number that can be described in an 8 bit word, which is 2 to the power 8 or 256.

If you have another light and switch this is doubled to 512 combinations.

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By (user no longer on site)
over a year ago

Why the fuck does anyone need that many lights?

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By *idingout41 OP   Man
over a year ago

Southampton


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions"

Thanks

Obvious really.

Although I think the answer is 2 to the power of 12 as one of the 8 switches turns on the five freestanding lamps and each has its own independent inline switch

So 4096 options

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By (user no longer on site)
over a year ago

Lamps glow.

Bulbs grow.

it's important to remember that

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By *ex HolesMan
over a year ago

Up North


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?"

Yes for employing such a shite electrician

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By *ensuallover1000Man
over a year ago

Somewhere In The Ether…

I got an ‘E’ in maths (‘Excellence’?)

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By (user no longer on site)
over a year ago

Two rows of spotlights, two switches. So much bloody easier.

Answer, have a smaller kitchen.

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By (user no longer on site)
over a year ago


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions

Thanks

Obvious really.

Although I think the answer is 2 to the power of 12 as one of the 8 switches turns on the five freestanding lamps and each has its own independent inline switch

So 4096 options "

Last one out turn the god damn lights out he's used enough electricity to power Blackpool lights

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By (user no longer on site)
over a year ago

I cant get past 40 bulbs in a room, do you live underground?

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By *idingout41 OP   Man
over a year ago

Southampton


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions

Thanks

Obvious really.

Although I think the answer is 2 to the power of 12 as one of the 8 switches turns on the five freestanding lamps and each has its own independent inline switch

So 4096 options

Last one out turn the god damn lights out he's used enough electricity to power Blackpool lights "

All low energy LEDs

They are not all used at the same time. The whole point of the bank of switches is that lots of different moods can be created.

Just one switch is used normally.

The room is quite large 80m2 and 5m high in the centre. Think oak barn.

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By *ensualtouch15Man
over a year ago

ashby de la zouch


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions

Thanks

Obvious really.

Although I think the answer is 2 to the power of 12 as one of the 8 switches turns on the five freestanding lamps and each has its own independent inline switch

So 4096 options

Last one out turn the god damn lights out he's used enough electricity to power Blackpool lights

All low energy LEDs

They are not all used at the same time. The whole point of the bank of switches is that lots of different moods can be created.

Just one switch is used normally.

The room is quite large 80m2 and 5m high in the centre. Think oak barn."

Infact I've decided

The bulbs are pure red herring

Switch has two states

Regardless of bulb configuration it's always going to be

2 to the power of switches or less

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By (user no longer on site)
over a year ago

After reading this my lights have fused

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By *uliaChrisCouple
over a year ago

westerham


"I was trying to explain this to my nine year old. I blame the wine but I ran into trouble.

Our open plan living room has 40 bulbs/ lamps

However the important bit is they are controlled by 8 switches. All are on or off apart one that switches a circuit of 5 independent lights.

My maths says there are 126 million lighting permutations.

Am I mad?

Ok

It seems you have

2 to the power 9

2 to the 8 covers the 8 switches and most lights

With a doubling of permutations for the independent 5

2to the 8 is 256

Thus 512 combinations

The number of lamps is irrelevant as you suggest they go on and off as one unit

So for simply

You have 8 binary switches that control one lamp with 40 bulbs

And one switch that controls one lamp with 5 bulbs

If so 512 positions

Thanks

Obvious really.

Although I think the answer is 2 to the power of 12 as one of the 8 switches turns on the five freestanding lamps and each has its own independent inline switch

So 4096 options "

Not being funny but that’s the sort of question my brother would pose as a riddle, and managing to omit the vital information- in this case that there’s another switch for each of the five lights, ie 14 switches in total....

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By (user no longer on site)
over a year ago

Sounds like some confused thinking going on.

The possible combinations of the 40 lights is factorial 40.

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By *ensualtouch15Man
over a year ago

ashby de la zouch


"Sounds like some confused thinking going on.

The possible combinations of the 40 lights is factorial 40.

"

Not with 11 14 15 8 switches it isnt

And factorials work when numbers are not repeated

So simply youre just completely wrong x

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By *ensualtouch15Man
over a year ago

ashby de la zouch


"Sounds like some confused thinking going on.

The possible combinations of the 40 lights is factorial 40.

"

One switch

Regardless equals two possibly

Regardless of light number

2 switches gives maximum of four regardless of configuration however less could be wired configured

3 8 maximum yet two switches giving a bank a binary option would reduce the combination

We need to differentiate also between max switch position combinations and the actual lights lit combinations which as I say although can be wired to match the switches they cannot exceed 2 to power switches and can be less xx

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